So, subtracting '20:31:00' from '23:00:00' gives 22900, meaning 2 hours 29 minutes 00 seconds. The part can be the day of the date, month of the date, year of the date etc. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). 1. 1 year and 2 months. You'd like to calculate the difference between arrival and departure and the number of days from arrival to departure inclusively. Weeks, quarters, and years follow from that. LogType, Feeds. 3 and above. SQL Server DATEPART() function overview. Summary: in this tutorial, you will learn how to use the SQL Server DATEPART() function to extract a part of a date. In PostgreSQL, you can take the difference in years, multiply by 12 and add. 0. DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) (sql) The DATEDIFF() function accepts three arguments: date_part , start_date , and end_date . 最後更新: 2020-02-06 勘誤回報. – The syntax for DATEDIFF is pretty straightforward: DATEDIFF (datepart, startdate, enddate) Let’s explore the parameters used here: datepart: The unit of time you want to use for the calculation, like year, quarter, month, day, or even smaller units like hour, minute, or second. Example 5: Use Current Date. Difference between two dates returned in hours,minutes,seconds. 8. The datepart passed to DATEDIFF will control the resolution of the output. –11. MySQL TIMEDIFF() With Large Values. The following. The math is 100% accurate for dates within a couple of hundred years or so. sql-server. One practical example of using the DATEDIFF function in SQL Server is in a WHERE clause by selecting all employees in the AdventureWorks2008R2 database whose date of hire was in March 2003. Follow. How to calculate age in SQL view. First, here’s the syntax: DATEDIFF(expr1,expr2) Where expr1 is the first date,. October 10, 2023. YEAR. This function accepts three parameters − the type of interval to measure (such as year, quarter, month, hour, minute, etc. I have two columns that have time data that looks like "2017-12-06 18:50:27 +0000" . MySQL 将timediff输出转换为天、小时、分钟、秒的格式 在MySQL中，timediff函数用于计算两个时间之间的差异。当我们使用timediff函数后，它将返回一个时间差，并以时、分、秒格式表示。但是，有时候我们需要将时间差转换为更易读的格式，例如天、小时、分钟和秒。Edit the SQL Statement, and click "Run SQL" to see the result. Syntax TIMEDIFF ( time1, time2) 1. year: January 1; quarter: January 1, April 1, July 1, October 1; month: the first day of the month; week:. USE TIMESTAMPDIFF MySQL function. Edit the SQL Statement, and click "Run SQL" to see the result. 0 indicates weak or no similarity between the SOUNDEX values. So, the difference between Jan 1 20015 and Dec 31 2016 is 1 year. TIME TIMEDIFF (DATETIME expr1, DATETIME expr2) TIMEDIFF returns the difference between two DATETIMEs. SELECT id, timeIn, timeOut, TIMEDIFF ( timeOut, timeIn ) AS timeDifference FROM table WHERE TIMESTAMPDIFF ( SECOND, timeOut, timeIn ) > 180000; This statement will output the fields for each record where the difference between the two timedates is one second or more over 50 hours (or 180000 seconds ). {fn TIMESTAMPDIFF (interval,startDate,endDate)} returns the difference between the starting and ending timestamps ( startDate minus endDate) for the specified date part interval (seconds, days, weeks, and so on). 8494441'. ) So, we can call DateDiff(second, Date1,Date2) and easily get the total number of seconds between. The TIMEDIFF() function returns the difference between two TIME values (time1 - time2) in the format 'HH:MM:SS'. select (test_time - sysdate)*24*60 from test; This value is negative if test_time is lies in. 23:00:00 or earlier. If you need the difference in seconds (i. MySQL TIMEDIFF() With Large Values. *,DATEDIFF(mi,c2. [GetBussinessDays] ('02/18/2021', '03/06/2021') -- 11 days CREATE or. it returns the difference in days if datepart is day. The way it works is, you provide two arguments (one for each date), and DATEDIFF() will return the number of days between the two dates. There aren't any duplicate entries in terms of time, the minimum time difference. W3Schools offers free online tutorials, references and exercises in all the major languages of the web. count will count all non-null values, so for else return NULL instead of zero. The two arguments of the function can either be hours (TIME) or dates with time (DATETIME), the result will be a time between “-838:59:59” and “838:59:59”. Subtracts the 2nd argument from the 1st (date1 − date2). DateTime startDate =. Get date difference. 6 Answers. numeric-expression. Column name), Column name) AS days_since_last FROM table name AS b. How to use TimeDiff function in Where clause. You don't specify the granularity you want for the diff. rn - 1 WHERE c1. TIMEDIFF(date1, date2) Arguments. Plus one for the example that shows GETDATE () and not just DATEDIFF, which is part of what OP needs. 0. The functions in this section use a format string that is compatible with JodaTime’s DateTimeFormat pattern format. Applies to: Databricks SQL Databricks Runtime 10. We will use the below date for the examples. So, we can use the TIMEDIFF() function with time values greater than 24 hours. timediff¶. datediff¶ pyspark. LogInOn – The column name which is to be subtracted. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. Edit the SQL Statement, and click "Run SQL" to see the result. 如需處理 startdate 與 enddate 值之間較大差異的函式，請參閱 DATEDIFF_BIG. Date Interval Calculation: The number of specified date parts between two provided dates is found using the DATEDIFF () method. The syntax for DATEDIFF is pretty straightforward: DATEDIFF (datepart, startdate, enddate) Let’s explore the parameters used here: datepart: The unit of time you want to use for the calculation, like year, quarter, month, day, or even smaller units like hour, minute, or second. Returns the difference between two timestamps measured in unit s. The integer value indicates the match for the two SOUNDEX values, from 0 to 4. g. spark. 000', @EndTime datetime = '2016-05-10 03:31:00. I have to show the difference, currently I used a datediff in the stored proc which just shows the difference of the days :( but i need to show the difference in days:hours:minutes:seconds if possible. The schema is SYSIBM. For example, the number of minutes between two datetime values evaluates the date component as well as the time component, and adds 1440 minutes for each day difference. 0000000'); --Syntax DATEDIFF ( datepart , startdate , enddate ) You can make use of DateDiff for this. DateValue > DateAdd (day,-3,getdate ()) doing this in this way makes your. 4. 1. Syntax. There's no built-in function - but you could relatively easily write your own T-SQL stored function to calculate this - something like this: CREATE FUNCTION dbo. The syntax for the DATEDIFF function is as follows: DATEDIFF(datepart, startdate, enddate)All datediff() does is compute the number of period boundaries crossed between two dates. Abbrevations. DATE_ADD () Add time values (intervals) to a date value. I need to compare 2 dates and return the number of days in between with 2 decimal places. The resulting column will be in INTERVAL DAY TO SECOND. Covering popular subjects like HTML, CSS, JavaScript, Python, SQL, Java, and many, many more. SQL Server Syntax DATEDIFF(datePart, date1, date2) The DATEDIFF() function in SQL Server has three required parameters:. Datediff () will also allow you to take month, hour, or other time measures. Run SQL ». Tried now the following that I got from : MySQL GROUP BY DateTime +/- 3 seconds but also no joy yet. String concatenation will build '1' + ',' + '27'. Create a calendar table, with every date of interest (so, something like 2000-01-01 to 2099-01-01) and include columns such as is_working_day which can be set to TRUE/FLASE or 1/0. SQL 語法. Example: In the travel table, there are three columns: id, departure, and arrival. , begin is a DATE value and end is a DATETIME value. Both arguments of this function must be of same type (either time or date-time) . Here expr2 is greater than expr1, so the return value is positive. DATE_SUB () Subtract a time value (interval) from a date. sql. If start is greater than end the result is negative. Summary: in this tutorial, you will learn how to use the SQL DATEPART () function to return a specified part of a date such year, month, and day from a given date. In DB2 the result of the subtraction of two TIME values is a duration, a DECIMAL in the form HHMMSS. The TIMESTAMPDIFF function allows its arguments to have mixed types e. 指定された日付または時刻の部分に基づいて、2つの日付、時刻、またはタイムスタンプ式の差を計算します。この関数は、3番目の引数から2番目の引数を減算した結果を返します。 datediff の代替です。 SELECT DATEDIFF (month,'2011-03-07' , '2021-06-24'); In this above example, you can find the number of months between the date of starting and ending. #1752702. startdate: The starting datetime value. In this article: Syntax. 8494441'. To find the date difference in minutes from the given DateTime values, use the following steps: - First, find the “date_diff” in days and multiply it with “24”. 1. Weeks, quarters, and years follow from that. In MySQL, you can use TIMESTAMPDIFF function. Syntax: Application. So DATEDIFF () returns the same result as in the previous example. DATEDIFF returns the count of the specified date part boundaries crossed between. Solution 1 (difference in seconds): The result is: Discussion: To calculate the difference between the arrival and the departure in T-SQL, use the DATEDIFF (datepart, startdate,. SQL Server DATEDIFF() 函数 SQL Server Date 函数 定义和用法 DATEDIFF() 函数返回两个日期之间的天数。 语法 DATEDIFF(datepart,startdate,enddate) startdate 和 enddate 参数是合法的日期表达式。datepart 参数可以是下列的值： datepart 缩写 年 yy, yyyy 季度 qq, q 月 mm, . SparkSQL - Difference between two time stamps in minutes. expr1 and expr2 are date or date-and-time expressions. The T-SQL DATEDIFF is defined as a primary function in T-SQL that can be used to find the difference between two date-utilities in which it has been utilized to differentiate between two date values having various date parts. If year numbers are different calculation of 52 * year difference + week number. Datediff will return 1 (when you use dd or equivalent), because the day part of the 2nd date is one more than the 1st. Time' How to repeat: ResultSet result = getConnection (). All of this is well documented in MySQL Date and Time functions. Use DATEADD (): where HireDate < dateadd (year, -3, GETDATE ()) DATEDIFF () does not do what you think it does. If you need the number of fractional hours, you can use DATEDIFF at a higher resolution and divide the result: DATEDIFF(second, start_date, end_date) / 3600. , between two dates. 6 = Friday. (ORDER BY [seat number])rr FROM #test) SELECT c1. DECLARE @null time; SET @null = '00:00:00'; SELECT DATEADD(SECOND, - DATEDIFF(SECOND, End_Time, Start_Time), @null) Reference: Time Difference Edit: As per the comment, if the difference between the end time and the start time might be negative, then you need to use a case statement as suchDescription. #1582 - Incorrect parameter count in the call to native function 'DATEDIFF'. This is because it only compares the date values (it ignores any time values). Then you can update that column as necessary, and join on that table in your query to get working dates that the employee has booked off. Applies to: SQL Server 2016 (13. This function takes three arguments: the start date, the end date, and the unit of time you want to measure. Use DateDiff function to match two columns. Cú pháp sử dụng hàm DATEDIFF () Hàm DATEDIFF () được sử dụng để kiểm tra sự khác biệt giữa hai khoảng thời gian, cú pháp của hàm DATEDIFF () như sau: DATEDIFF(interval, date1, date2) Tham số: interval là khoảng sử dụng. 1. TIMEDIFF(time1, time2) 差分の時間は time1 - time2 で計算されます。. The next example will show the differences between two dates for each specific datapart and abbreviation. datePart is the part of the date to return. If you need the number of fractional hours, you can use DATEDIFF at a higher resolution and divide the result: DATEDIFF(second, start_date, end_date) / 3600. Teams. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual;. e. To do this, we need to create a calculated column using the DATEDIFF DAX function as seen in the diagram and DAX syntax below. The following illustrates the syntax of the DATEDIFF () function in SQL Server:. TIMEDIFF () returns expr1 - expr2 expressed as a time value. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. SELECT a1. Actually, the marked answer originally produced wrong results for milliseconds 1 - 99: Example 1 second, 27 milliseconds: DATEDIFF % 1000 will return 27. user_id, TIMEDIFF(MIN(t. Result is expressed as a time value (and it has the limitations of the time. Sorted by: 21. Share. You can add hours, minutes, seconds, and milliseconds at the same time in the time value. 0. The TIME_DIFF function allows you to find the difference between 2 time objects. Syntax TIMEDIFF( <date_or_time_part> , <date_or_time_expr1> , <date_or time_expr2> ) Arguments date_or_time_part The unit of time. Share. You could try the following. 9. The best will likely be: SELECT <column list> -- not * (1) FROM dbo. DateValue > DateAdd (day,-3,getdate ()) doing this in this way makes your. LogOutOn – The column name from which second parameter to subtract. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate. Here I need to calculate the difference of the two dates in the PostgreSQL. 0 and above. The SQL DATEDIFF function calculates and returns the difference between two date values. I came across an easier way of solving this issue. timestamp AS timediff FROM foo t1 inner join foo. MySQL: Select TIMEDIFF values where the difference is greater than x. DATE () Extract the date part of a date or datetime expression. 2. The difference between startdate and enddate is expressed in days. In SQL Server: Like we do in SQL Server its much easier. The DIFFERENCE () function compares two SOUNDEX values, and returns an integer. order_logs_created) FROM order_logs. Improve this answer. You can use the DATEDIFF function to get the difference in minutes, seconds, days etc. select datediff ('2019-02-01', '2019-01-27')/365. The Solution. 1. Pair ORDER BY T. If the returned result is out of range for 32-bit. 0. On Db2 11. Here is my existing SQL statement: SELECT TOP 10 Users. Multiply this by 48 to give the number of half-hour intervals. Hot Network QuestionsOctober 15, 2014 at 4:50 pm. From second to datetime sql server. It supports time series analysis by allowing you to calculate the time intervals between data points. It is the unit in which the DATEDIFF () function returns the difference between a start date and an end date e. SELECT *, ISNULL(DATEDIFF(mi, LAG(CreateDate,1) OVER (ORDER BY ID), CreateDate), 0) AS Duration. Using T-SQL DATEADD and DATEDIFF function. DATEDIFF,MaxCompute:Calculates the difference between date1 and date2. The DATEPART () function returns an integer value that represents a specified part of the date of a given date. Dive into its nuances, optimize its use, and transform the way you handle date-based tasks. DATEDIFF¶ Calculates the difference between two date, time, or timestamp expressions based on the date or time part requested. Overview: I have tables SHIFT_LOG, SHIFT_LOG_DET & SHIFT_LOG_ENTRY having Parent-Child-GrandChild relationships (one-to-many). The datepart passed to DATEDIFF will control the resolution of the output. Learn more about TeamsPySpark Timestamp Difference – Date & Time in String Format. datediff between multiple records in SQL. Column [source] ¶ Returns the number. mySql TimeDiff between TimeStamp in Rows of a Single Table. 4 and above. Table 9. format_datetime(timestamp, format) → varchar. select post_visid_high || ':' || post_visid_low as visitor_id , lag (date_time) over (partition by visitor_id order by date_time asc) as previous_date , datediff (minute, previous_date, date_time) as difference_in_minutes from adobe_data. As such, it is limited to the data type TIME. just substitute StartDate and EndDate for your column names, and tableName for the actual table name. Covering popular subjects like HTML, CSS, JavaScript, Python, SQL, Java, and many, many more. The query should only count the different date changes. DATEDIFF – Name of function. Learn more about TeamsDateDiff (String, Nullable<DateTime>, Nullable<TimeSpan>) Returns the count of the specified datepart boundaries crossed between the specified start date and end date. Return the current time. MySQLだけでDateTime - DateTimeなどの時間差分を取りたい…やり方を知らないとカラムA／Bの時間を別々に取得し、それをスクリプト側で計算みたいな遠回りをしがちです。ところがMySQLにはTIMEDIFF()という便利な関数が用意されてます。この関数が本当に便利なので、知らない人の為にTIMEDIFF()をまとめ. sql timediff function. 1. sql server function. The schema is SYSIBM. 'month' or month ). Both integer (int) and big integer (bigint) are numeric data types used to store integer values. TheDate = InputBox ("Enter a date") Msg = "Days from today: " & DateDiff ("d", Now, TheDate) MsgBox Msg. Consider SQL Server function to calculate the difference between 2 dates in years: . SELECT t. One month is considered elapsed when the calendar month has increased and the calendar day and time is equal or greater to the start. USE MASTER GO -. The TIMESTAMPDIFF function returns an estimated number of intervals of the type that is defined by the first argument, based on the difference between two timestamps. Here I need to calculate the difference of the two dates in the PostgreSQL. To measure the difference between two dates in units other than days use datediff (timestamp) function. 1. Covering popular subjects like HTML, CSS, JavaScript,. Difference will be calculated as startdate - enddate . SQL Server: -- Difference between Oct 02, 2011 and Jan 01, 2012 in years SELECT DATEDIFF (year, '2011-10-02', '2012-01-01'); -- Result: 1. Teams. Timestamp DESC. SELECT HOUR (TIMEDIFF (end_time, start_time)) as `difference` FROM timeattendance WHERE timeattendance_id = '1484'. DateDiff (String, Nullable<DateTime>, Nullable<DateTimeOffset>) Returns the count of the specified datepart boundaries crossed between the specified start date and end date. Returns the number of days from startDate to endDate. Specifies the first day of the week. CreatedDate) as Difference from Registration a1 inner join Registration a2 on. You don't specify the granularity you want for the diff. 0. Requires 3 arguments. Sorted by: 21. datediff(endDate, startDate) Arguments. select datediff (dd,convert (date,date2),convert (date,date1)) From Yourtable. sqlserver. ), the start date or time that specifies the beginning of the period. It returns an integer value that represents the number of specified date or time units between two dates or times. If you are using MySQL there is the DATEDIFF function which calculate the days between two dates: SELECT dtCreated , bActive , dtLastPaymentAttempt , dtLastUpdated , dtLastVisit , DATEDIFF (dtLastUpdated, dtCreated) as Difference FROM Customers WHERE (bActive = 'true') AND (dtLastUpdated > CONVERT (DATETIME,. The format of the timediff() result is designed to be human-readable. We can say that if the current event has occurred prior to or is occurring on the date the individual will have a birthday that year, then use the age produced by the DATEDIFF. SELECT DATEDIFF (YY,'01/02/2011 15:00:00','01/01/2016 14:00:00') 5. USER_FECHA_INCORPORACION, AGENTE. startDate: A DATE expression. It shows us that there are 36 hours, 15 minutes, and 35 seconds between the two date-and. You can't display more than 24 hours in a time format 00:00, so you need to choose a different way to display the output. Given a unit of SECOND, TIMESTAMPDIFF() is a more robust solution. Or in another words, I want to write a. DATEDIFF() is a function found in SQL Server and MySQL that calculates and returns the difference between two date values. Subtracts the 2nd argument from the 3rd (date2 − date1). I know there is one inbuilt function DATEDIFF for this but i want some custom fractional difference like: sDate. Like the two fields are sale_start_date. UserID = Users. It's possible to calculate the next date, and then use datediff/timediff to find the seconds to next day, and convert the result to timestamp. 6222691' DECLARE @date2 datetime2 = '2022-01-14 12:32:07. Parse [ ^] to parse it. First, a quick example of turning a "number of seconds" into the "hh:mm:ss" format. For example, TIMEDIFF() outputs is hours, minutes, seconds. functions val df2 = df1. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff. DATEDIFF - Display result in Hours and minutes. t2 on t1. Syntax: The following syntax can be used in a SQL query: SELECT TIMEDIFF(hour1,. 1. In MySQL, you can use the DATEDIFF() function to find the difference between two dates. 0. Also, you can swap out the 'd' character for other dateparts, say if you wanted to find the date difference in months, years etc. 53. 1 Answer. In this article, Let us see a Spark SQL Dataframe example of how to calculate a Datediff between two dates in seconds, minutes, hours, days, and months using Scala language and functions like datediff(), unix_timestamp(), to_timestamp(), months_between(). Datediff SQL is key for developers, enabling accurate date calculations. The result is a signed integer value equal to (date-expression-2 - date-expression-1), in date parts. CONVERT will convert to '27'. SQL Server DATEDIFF function returns the difference in seconds, minutes, hours, days, weeks, months, quarters and years between 2 datetime values. The second parameter of DATEDIFF takes a datetime so your string is implicitly converted to a datetime. I cannot figure out how to functional query in mysql, Can you give some information of how can achieve this with mysql query. DATEDIFF¶ Calculates the difference between two date, time, or timestamp expressions based on the date or time part requested. executeQuery (); while. Find the interval between today's date and a column. Before using Datediff use Convert function to convert the varchar data into date. You can't use aliases you created in the SELECT clause elsewhere in the same SELECT clause, so you need to place your FIRST_VALUE () and LAST_VALUE () functions within the DATEDIFF () function: SELECT DISTINCT Test, FIRST_VALUE (CONVERT (DATE, datetime)) OVER (ORDER BY datetime DESC) StartDate,. W3Schools offers free online tutorials, references and exercises in all the major languages of the web. La función DATEDIFF() en SQL devuelve la diferencia entre dos fechas. SQL DATEPART. W3Schools offers free online tutorials, references and exercises in all the major languages of the web. DateDiff in SQL. The following shows the syntax of the DATEPART() function:. With the birth of SQL Server 2016, Microsoft has introduced a new DATEDIFF SQL function, an enhanced version of DATEDIFF known as DATEDIFF_BIG. The TO_DAYS () function returns the number of days between a date and year 0 (date "0000-00-00"). The TIMESTAMPDIFF function returns the result of begin - end, where begin and end are DATE or DATETIME expressions. This SQL Server scripts uses the DATEDIFF function and calculate difference in hours, minutes, and. Connect and share knowledge within a single location that is structured and easy to search. mysql: convert timediff() to seconds. The MYSQL TIMEDIFF() function accepts two time or, date-time values as parameters, calculates the difference between them (argument1-argument2) and returns the result. To get time difference between datetime or smalldatetime columns you can use DATEDIFF function. 0. datediff (to_date (String timestamp), to_date (String timestamp)) SELECT datediff (to_date ('2019-08-03'), to_date ('2019-08-01')) <= 2; to_date is unnecessary if the column is already in 'yyyy-mm-dd' format. SELECT DATEDIFF(end_date, start_date) from accounts But, I don't know how am I supposed to do it in MySQL, I found this article Count days between two dates, excluding weekends (MySQL only) . SELECT COUNT (liter),DAY (dater),HOUR (dater),MINUTE (dater) FROM watermeter JOIN (SELECT watermeter. How to compare two dates ignoring seconds in sql server. of days between two given dates. Return Type. Date Part Intervals. 0. answered Sep 27, 2011 at 19:42. We will use the below. To get the difference in hours, choose hour. 在 SQL Server 中，我們可以用 DATEDIFF() 函數取得兩個日期之間相差的時間間隔。 DATEDIFF() 語法 (Syntax) DATEDIFF(datepart, startdate, enddate) DATEDIFF() 執行後會返回一個正負樹的整數，表示 enddate - startdate 的時間間隔，datepart 參數則用來指定返回值. So Update one does not give me the correct result. I am using SQL SERVER. 0. If you want hour to be very specific, you can use as given below: Declare @Start DateTime = '1/1/17 7:59 AM' Declare @End Datetime = '1/1/17 8:00 AM' select DATEDIFF (MINUTE, @Start, @end) /60 AS Hour. Theese examples give you an idea of what I mean: SELECT DATEDIFF(YY, '31/12/2016', '01/01/2017') FakeYears FakeYears 1 SELECT DATEDIFF(HOUR, '01/01/2017 00:59:59', '01/01/2017 01:00:00'). Add a comment. The SQL DATEDIFF () is a function, and use to find the difference between two dates. 0000000' , '2014-03-19 07:20:00. 0. This function allows you to obtain data from the previous record (based on an order criterion, which here is “ ORDER BY year ”). W3Schools offers free online tutorials, references and exercises in all the major languages of the web. Syntax. However I see two disadvantages with this method. 3. If either startdate or enddate have only a time part and the other only a date part, DATEDIFF sets the missing time and date parts to the default values. This function is a synonym for timestampdiff function. I need the Oracle equivalent to the SQL Server DATEDIFF function to compute the difference between two dates. #.